Scaling from an 8 inch to a 9 inch pan

[aidensnd2]

I'm converting a recipe that was written for an 8 inch pan into a 9 inch pan. It seems to me that 125% of the original would be correct. Does that sound right to you guys?

Thanks.

[culinary bear]

I'm converting a recipe that was written for an 8 inch pan into a 9 inch pan. It seems to me that 125% of the original would be correct. Does that sound right to you guys?

Thanks.

←

Assuming that the depth of the mix in both pans is the same, then the surface area is the important variable:

surface area of 8" pan = pi x r x r = 64 x pi

surface area of 9' pan = 81 x pi

differential = 81/64 x 100 = 126.56, which is as near as makes no difference to 125%.

edited to add : I wonder if conversion tables are available for instances such as these? square to round pans, different sizes, depths, that sort of thing?

Edited February 2, 2005 by culinary bear (log)

[Anna N]

I'm converting a recipe that was written for an 8 inch pan into a 9 inch pan. It seems to me that 125% of the original would be correct. Does that sound right to you guys?

Thanks.

←

Assuming that the depth of the mix in both pans is the same, then the surface area is the important variable:

surface area of 8" pan = pi x r x r = 64 x pi

surface area of 9' pan = 81 x pi

differential = 81/64 x 100 = 126.56, which is as near as makes no difference to 125%.

edited to add : I wonder if conversion tables are available for instances such as these? square to round pans, different sizes, depths, that sort of thing?

←

Like this?

pan size substitution chart

[Dorie Greenspan]

www.pastryscoop.com has an easy-to-use pan volume chart . There are also other useful conversion charts on the site.

[rjwong]

Assuming that the depth of the mix in both pans is the same, then the surface area is the important variable:

surface area of 8" pan = pi x r x r = 64 x pi

surface area of 9' pan = 81 x pi

differential = 81/64 x 100 = 126.56, which is as near as makes no difference to 125%.

←

culinary bear,

The radius of an 8" pan is 4". The radius of an 9" pan is 4.5".

Thus,

surface area of 8" pan = πr² = 3.14 x 4 x 4 = 50.24

surface area of 9' pan = 3.14 x 4.5 x 4.5 = 63.58

differential = 63.58/50.24 x 100 = 1.26

Mind you, the differential is still close to 125%.

Therefore, to answer aidensnd's question: Yes, 125% seems correct.

[chiantiglace]

HAHA, rj i started posting the exact same thing but once i was about to post i noticed your reply.

It doesnt really matter, 100% or 200%. It's still being dstributed the same.

But still funny.

[aidensnd2]

Thanks for all the input. I made the recipe at 125% and it worked out perfect.

Thanks again.