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paulraphael

paulraphael

34 minutes ago, Duvel said:


Yeap. At 0 oC, and you pay for that by diluting your drink. If you don’t want that, please see above 😉

 

Chilling is proportional to dilution, no matter how far you chill. Dave specifically demonstrates this. The amount of chilling due to conductivity, or the coldness of the ice, is negligible. 

 

Ice’s tremendous chilling power doesn’t come from the energy required to heat it up, but from the energy required to melt it. It takes 0.5 calories to heat a gram of ice from -1°C to 0°C (this value is called the specific heat of ice,) but almost 80 calories to melt that same gram (this value is called the heat of fusion of water). To put it another way, melting 1 gram of ice provides the same chilling power as bringing that same gram of ice from -160°C to 0°C.

paulraphael

paulraphael

33 minutes ago, Duvel said:


Yeap. At 0 oC, and you pay for that by diluting your drink. If you don’t want that, please see above 😉

 

All chilling is proportional to dilution, no matter how far you chill. Dave specifically demonstrates this. The amount of chilling due to conductivity, or the coldness of the ice, is always minor. 

 

Ice’s tremendous chilling power doesn’t come from the energy required to heat it up, but from the energy required to melt it. It takes 0.5 calories to heat a gram of ice from -1°C to 0°C (this value is called the specific heat of ice,) but almost 80 calories to melt that same gram (this value is called the heat of fusion of water). To put it another way, melting 1 gram of ice provides the same chilling power as bringing that same gram of ice from -160°C to 0°C.

paulraphael

paulraphael

22 minutes ago, Duvel said:


Yeap. At 0 oC, and you pay for that by diluting your drink. If you don’t want that, please see above 😉

 

All chilling is proportional to dilution, no matter matter how far you chill. Dave specifically demonstrates this. The amount of chilling due to conductivity, or the coldness of the ice, is always minor. 

 

Ice’s tremendous chilling power doesn’t come from the energy required to heat it up, but from the energy required to melt it. It takes 0.5 calories to heat a gram of ice from -1°C to 0°C (this value is called the specific heat of ice,) but almost 80 calories to melt that same gram (this value is called the heat of fusion of water). To put it another way, melting 1 gram of ice provides the same chilling power as bringing that same gram of ice from -160°C to 0°C.

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